برنامه نویسی کمک در این خطا

[shamimi]

سلام دوستان من این کد و نوشتم از روی یک کتاب دیتابیس ایناشم همه درسته ولی یه خطای جالب می ده که به <؟ خطا می ده و اجرا نمی کسی میتونه چک کنه
خودش با اجرا دیتابیس و درست می کنه

<?php
$link = mysql_connect("localhost","root","")
or die(mysql_error());
mysql_select_db("moviesite")
or die (mysql_error());
$query = "SELECT movie_name, movie_director, movie_leadactor " .
"FROM movie";
$result = mysql_query($query, $link)
or die (mysql_error());
$num_movies = mysql_num_rows($_result);
 
$movie_header=<<<EOD
<h2><center>Movie Review Database</center></h2>
<table width="70%" border="1" cellpadding="2" cellspacing="2" align="center">
<tr>
<th>Movie Title</th>
<th>Movie Director</th>
<th>Movie Lead Actor</th>
</tr>
EOD;

function get_director() {
    global $movie_director;
    global $director;
    
    $query_d = "SELECT people_fullname " .
    "FROM people " .
    "WHERE people_id='$movie_director'";
    $results_d = mysql_query($query_d)
    or die (mysql_error());
    $row_d = mysql_fetch_array($results_d);
    extract($row_d);
    $director = $people_fullname;
}
function get_leadactor() {
    global $movie_leadactor;
    global $leadactor;
    
    $query_a = "SELECT people_fullname " .
    "FROM people " .
    "WHERE people_id='$movie_leadactor'";
    $results_a = mysql_query($query_a)
    or die (mysql_error());
    $row_a = mysql_fetch_array($results_a);
    extract($row_a);
    $leadactor = $people_fullname;
}

while ($row = mysql_fetch_array($result)) {
    $movie_name = $row['movie_name'];
    $movie_director = $row['movie_director'];
    $movie_leadactor = $row['movie_leadactor'];
    
    //get director's name from people table
    get_director();
    //get lea actor's name from people table
    get_leadactor();
    
    $movie_details .=<<<EOD
    <tr>
    <td>$movie_name</td>
    <td>$director</td>
    <td>$leadactor</td>
    </tr>
    EOD;
}

$movie_details .=<<<EOD
<tr>
<td>Total :$num_movies Movies</td>
</tr>
EOD;

$movie_footer="</table>";
$movie =<<<MOVIE
       $movie_header
       $movie_details
       $movie_footer
MOVIE;
echo "There are $num_movies movies in our database";
echo $movie;
?>