کد PHP:<script type="text/javascript">
<?php
$squrl = null;
$urls = array(
'site1' => 'file1',
'site2' => 'file2',
'site3' => 'file3',
);
if(isset($_GET)) :
foreach ($_GET as $k=>$v) {
if (array_key_exists($k,$urls)) {
$squrl = @$urls[$k];
break;
}
} else echo 'n';
if($squrl) echo '
file: "'.$squrl.'",
';
else:
echo 'file: "defaultURL"';
endif;
?>
</script>





پاسخ با نقل قول